A yo-yo is resting on a perfectly rough horizontal table. Forces F 1 , F 2 , F 3 and F 4 are applied separately as shown.
Column I | Column II |
(i) | [A] Centre of mass accelerates towards left |
(ii) cos θ < | [B] Centre of mass accelerates towards Right |
(iii) cos θ > | [C] Friction acts towards left |
(iv) cos θ = | [D] Frication acts towards right |
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Ans.
(i) [B], [C]
(ii) [A], [C]
(iii) [B], [C]
(iv) [C]
Sol.
(i) 
a CM towards right and for clockwise α , f s leftwards check rotational motion ( α ) about centre
(ii) 
For (ii), taking Σ T about instantaneous centre of rotation (ICOR), α is anticlockwise hence for a CM = α R
a CM leftward and f s provides leftward a CM .
(iii) 
For (iii) taking Σ T about instantaneous centre of rotation (ICOR), α is clockwise hence a CM rightward and f s leftward to create clockwise α .
(iv) 
For (iv) Σ T = 0 about instantaneous centre of rotation (ICOR) ⇒ α = 0, a cm = 0.
No motion hence f s leftward to balance horizontal component of F.
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